oracle Chọn ngày cho các mặt hàng được bán cách nhau 1 phút

Bạn có thể sử dụng LAG / LEAD chức năng phân tích để so sánh các hàng trước đó và tiếp theo để xác định xem chúng có nằm trong vòng một phút so với hàng hiện tại hay không:

SELECT location,
       LISTAGG( equipment_type, ',' )
         WITHIN GROUP ( ORDER BY sold_date )
         AS equipment_types,
       LISTAGG( TO_CHAR( sold_date, 'HH24:MI:SS' ), ',' )
         WITHIN GROUP ( ORDER BY sold_date )
         AS sold_dates
FROM   (
  SELECT num_cars,
         equipment_type,
         location,
         sold_date,
         CASE
         WHEN within_minute_of_prev = 1 OR within_minute_of_next = 1
         THEN SUM(
                CASE
                WHEN within_minute_of_prev = 0 AND within_minute_of_next = 1
                THEN 1
                ELSE 0
                END
              ) OVER ( PARTITION BY location ORDER BY sold_date )
         END AS grp
  FROM   (
    SELECT c.*,
           CASE
           WHEN ( sold_date
                  - LAG( sold_date ) OVER ( PARTITION BY location ORDER BY sold_date )
                ) DAY TO SECOND
                <= INTERVAL '1' MINUTE
           THEN 1
           ELSE 0
           END AS within_minute_of_prev,
           CASE
           WHEN ( LEAD( sold_date ) OVER ( PARTITION BY location ORDER BY sold_date )
                  - sold_date
                ) DAY TO SECOND
                <= INTERVAL '1' MINUTE
           THEN 1
           ELSE 0
           END AS within_minute_of_next
    FROM   car_sales c
  )
)
WHERE grp IS NOT NULL
GROUP BY location, grp;

Cái nào, cho dữ liệu mẫu của bạn:

CREATE TABLE CAR_SALES ( NUM_CARS, EQUIPMENT_TYPE, LOCATION, SOLD_DATE ) AS
  SELECT   8, 'Rovers',   'coventry',   DATE '2019-09-07' + INTERVAL '10:00:12' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   1, 'Rovers',   'coventry',   DATE '2019-09-07' + INTERVAL '10:00:45' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   9, 'Jaguars',  'coventry',   DATE '2019-09-07' + INTERVAL '06:00:00' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   7, 'Rovers',   'leamington', DATE '2019-08-30' + INTERVAL '13:10:13' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT  10, 'Trans Am', 'leamington', DATE '2019-08-30' + INTERVAL '09:00:00' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   2, 'Trans Am', 'leamington', DATE '2019-08-30' + INTERVAL '13:10:48' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   8, 'Rovers',   'coventry',   DATE '2019-09-06' + INTERVAL '18:00:00' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   4, 'Rovers',   'leamington', DATE '2019-09-06' + INTERVAL '09:00:00' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT 100, 'Trans Am', 'leamington', DATE '2019-09-06' + INTERVAL '08:59:45' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   1, 'corvette', 'leamington', DATE '2019-09-06' + INTERVAL '09:00:10' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   2, 'Toyota',   'coventry',   DATE '2019-09-06' + INTERVAL '10:00:00' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT  15, 'Rovers',   'coventry',   DATE '2019-09-07' + INTERVAL '11:05:00' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   2, 'Jaguars',  'coventry',   DATE '2019-09-07' + INTERVAL '17:02:07' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   3, 'Trans Am', 'leamington', DATE '2019-08-30' + INTERVAL '13:10:25' HOUR TO SECOND FROM DUAL;

Kết quả đầu ra:

db <> fiddle tại đây

Cập nhật

Một truy vấn Oracle 12c ngắn hơn nhiều sử dụng MATCH_RECOGNIZE :

SELECT location,
       LISTAGG( equipment_type, ',' )
         WITHIN GROUP ( ORDER BY sold_date )
         AS equipment_types,
       LISTAGG( TO_CHAR( sold_date, 'HH24:MI:SS' ), ',' )
         WITHIN GROUP ( ORDER BY sold_date )
         AS sold_times
FROM   car_sales
MATCH_RECOGNIZE (
   PARTITION BY location
   ORDER BY sold_date
   MEASURES  
      MATCH_NUMBER() AS mno
   ALL ROWS PER MATCH
   PATTERN (A B+)
   DEFINE
      B AS B.sold_date <= PREV(B.sold_date) + interval '1' minute
)
GROUP BY location, mno
ORDER BY location, mno;

Mà, đối với dữ liệu thử nghiệm:

CREATE TABLE CAR_SALES ( NUM_CARS, EQUIPMENT_TYPE, LOCATION, SOLD_DATE ) AS
  SELECT   8, 'Rovers',   'coventry',   DATE '2019-09-07' + INTERVAL '10:00:12' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   1, 'Rovers',   'coventry',   DATE '2019-09-07' + INTERVAL '10:00:45' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   3, 'Rovers',   'coventry',   DATE '2019-09-07' + INTERVAL '10:01:15' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   3, 'Rovers',   'coventry',   DATE '2019-09-07' + INTERVAL '10:01:30' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   9, 'Jaguars',  'coventry',   DATE '2019-09-07' + INTERVAL '06:00:00' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   7, 'Rovers',   'leamington', DATE '2019-08-30' + INTERVAL '13:10:13' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT  10, 'Trans Am', 'leamington', DATE '2019-08-30' + INTERVAL '09:00:00' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   2, 'Trans Am', 'leamington', DATE '2019-08-30' + INTERVAL '13:10:48' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   8, 'Rovers',   'coventry',   DATE '2019-09-06' + INTERVAL '18:00:00' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   4, 'Rovers',   'leamington', DATE '2019-09-06' + INTERVAL '09:00:00' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT 100, 'Trans Am', 'leamington', DATE '2019-09-06' + INTERVAL '08:59:45' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   1, 'corvette', 'leamington', DATE '2019-09-06' + INTERVAL '09:00:10' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   2, 'Toyota',   'coventry',   DATE '2019-09-06' + INTERVAL '10:00:00' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT  15, 'Rovers',   'coventry',   DATE '2019-09-07' + INTERVAL '11:05:00' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   2, 'Jaguars',  'coventry',   DATE '2019-09-07' + INTERVAL '17:02:07' HOUR TO SECOND FROM DUAL UNION ALL
  SELECT   3, 'Trans Am', 'leamington', DATE '2019-08-30' + INTERVAL '13:10:25' HOUR TO SECOND FROM DUAL;

Kết quả đầu ra:

db <> fiddle tại đây