Chọn các hàng khi giá trị cột thay đổi giữa các ngày trong Oracle?

Bạn có thể sử dụng COUNT( DISTINCT code ) OVER ( PARTITION BY id ) chức năng phân tích để nhận câu trả lời của bạn chỉ bằng một lần quét bảng:

SQL Fiddle

Thiết lập lược đồ Oracle 11g R2 :

CREATE TABLE table_name ( ID, Code, "DATE" ) AS
SELECT 1, 'A', DATE '2018-02-19' FROM DUAL UNION ALL
SELECT 1, 'B', DATE '2018-02-18' FROM DUAL UNION ALL
SELECT 1, 'B', DATE '2018-02-17' FROM DUAL UNION ALL
SELECT 1, 'B', DATE '2018-02-16' FROM DUAL UNION ALL
SELECT 2, 'A', DATE '2018-02-17' FROM DUAL UNION ALL
SELECT 2, 'B', DATE '2018-02-16' FROM DUAL UNION ALL
SELECT 3, 'A', DATE '2018-02-17' FROM DUAL UNION ALL
SELECT 3, 'A', DATE '2018-02-16' FROM DUAL UNION ALL
SELECT 4, 'D', DATE '2018-02-16' FROM DUAL;

Truy vấn 1 :

SELECT ID,
       Code,
       "DATE"
FROM   (
  SELECT t.*,
         COUNT( DISTINCT code ) OVER ( PARTITION BY id ) AS num_changes
  FROM   table_name t
  WHERE  "DATE" BETWEEN DATE '2018-02-16'
                    AND DATE '2018-02-19'
)
WHERE num_changes > 1

Kết quả :

| ID | CODE |                 DATE |
|----|------|----------------------|
|  1 |    A | 2018-02-19T00:00:00Z |
|  1 |    B | 2018-02-18T00:00:00Z |
|  1 |    B | 2018-02-17T00:00:00Z |
|  1 |    B | 2018-02-16T00:00:00Z |
|  2 |    A | 2018-02-17T00:00:00Z |
|  2 |    B | 2018-02-16T00:00:00Z |

Truy vấn 2 :

SELECT ID,
       Code,
       "DATE"
FROM   (
  SELECT t.*,
         COUNT( DISTINCT code ) OVER ( PARTITION BY id ) AS num_changes
  FROM   table_name t
  WHERE  "DATE" BETWEEN DATE '2018-02-16'
                    AND DATE '2018-02-18'
)
WHERE num_changes > 1

Kết quả :

| ID | CODE |                 DATE |
|----|------|----------------------|
|  2 |    A | 2018-02-17T00:00:00Z |
|  2 |    B | 2018-02-16T00:00:00Z |