WITH RECURSIVE parent_line(path, id) AS (
SELECT ARRAY[(row_number() OVER (PARTITION BY CP.idc))::integer], C.id
FROM categorias C JOIN categ_parents CP ON C.id = CP.idparent
WHERE CP.idc = 36
UNION ALL
SELECT PL.path || (row_number() OVER (PARTITION BY PL.id))::integer,
C.id
FROM categorias C
JOIN categ_parents CP ON C.id = CP.idparent
JOIN parent_line PL on CP.idc = PL.id
),
real_parent_line(path, chainid, id) AS (
SELECT PL.path, (row_number() OVER (PARTITION BY PL.id)),
PL.id
FROM parent_line PL
WHERE PL.id IN (
SELECT id
FROM categorias C LEFT JOIN categ_parents CP
ON (C.id = CP.idc)
WHERE CP.idc IS NULL
)
UNION ALL
SELECT PL.path, chainid, PL.id
FROM parent_line PL, real_parent_line RPL
WHERE array_upper(PL.path,1) + 1 = array_upper(RPL.path,1)
AND PL.path = RPL.path[1:(array_upper(RPL.path,1)-1)]
)
SELECT array_accum(id) AS ids
FROM real_parent_line RPL
GROUP BY chainid;
WITH
đầu tiên mệnh đề cho điều này:
path | id ------------------------ "{1}" 31 "{1,1}" 22 "{1,2}" 30 "{1,1,1}" 20 "{1,1,2}" 8 "{1,2,1}" 20 "{1,1,2,1}" 5 "{1,1,1,1}" 1 "{1,2,1,2}" 1 "{1,1,2,1,1}" 2 "{1,1,2,1,1,1}" 1 "{1,1,2,1,1,2}" 20 "{1,1,2,1,1,2,1}" 1
Cảm ơn # [email protected] để được trợ giúp.