Tạo một lược đồ cơ sở dữ liệu có thể mở rộng để lưu trữ điểm số chơi gôn

Điểm trung bình, cao nhất và thấp nhất của tôi là bao nhiêu?

Tình huống 1.

select (h1+h2+h3+h4+h5+h6+h7+h8+h9+h10+h11+h13+h14+h15+h16+h17+h18) / 18 as avg_score
      ,greatest(h1,h2,h3,h4,h5,h6,h7,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18) as highest
      ,least(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18) as lowest
  from scores
 where player_id = 1;

so với

select avg(score) as avg_score
      ,max(score) as highest
      ,min(score) as lowest
  from scores
 where player_id = 1;

Cái lỗ nào tồi tệ nhất của tôi?

Tình huống 2.

select case when h1 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18)  then 'H1'
            when h2 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18)  then 'H2'
            when h3 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18)  then 'H3'
            when h4 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18)  then 'H4'
            when h5 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18)  then 'H5'
            when h6 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18)  then 'H6'
            when h7 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18)  then 'H7'
            when h8 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18)  then 'H8'
            when h9 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18)  then 'H9'
            when h10 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18) then 'H10'
            when h11 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18) then 'H11'
            when h12 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18) then 'H12'
            when h13 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18) then 'H13'
            when h14 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18) then 'H14'
            when h15 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18) then 'H15'
            when h16 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18) then 'H16'
            when h17 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18) then 'H17'
            when h18 = greatest(h1,h2,h3,h4,h5,h6,h8,h8,h9,h10,h11,h12,h13,h14,h16,h17,h18) then 'H18'
        end as hole_highest_score      
  from scores
 where player_id = 1;

so với

select hole, score
  from scores s1
 where player_id = 1
   and score = (select max(score)
                  from scores s2
                 where s2.player_id = s1.player_id)

Tôi sẽ làm với kịch bản 2 bất cứ ngày nào :)