select
(select p.ProblemType as 'td' for xml path(''), type),
(select p.Onset as 'td' for xml path(''), type),
(select p.DiagnosisStatus as 'td' for xml path(''), type)
from tblProblemList p
where p.PatientUnitNumber = @PatientUnitNumber
for xml path('tr')
Để thêm tiêu đề, bạn cũng có thể sử dụng union all
.
select
(select 'Problem' as th for xml path(''), type),
(select 'Onset' as th for xml path(''), type),
(select 'Status' as th for xml path(''), type)
union all
select
(select p.ProblemType as 'td' for xml path(''), type),
(select p.Onset as 'td' for xml path(''), type),
(select p.DiagnosisStatus as 'td' for xml path(''), type)
from tblProblemList p
where p.PatientUnitNumber = @PatientUnitNumber
for xml path('tr')