Tôi không khuyến nghị điều này, nhưng tôi đã xoay sở để giải quyết nó.
Bảng:
CREATE TABLE [dbo].[names](
[id] [int] NULL,
[myId] [int] NULL,
[name] [char](25) NULL
) ON [PRIMARY]
Dữ liệu:
INSERT INTO names values (1,3,'Bob')
INSERT INTO names values 2,3,'Chet')
INSERT INTO names values 3,3,'Dave')
INSERT INTO names values 4,4,'Jim')
INSERT INTO names values 5,4,'Jose')
INSERT INTO names values 6,5,'Nick')
Truy vấn:
WITH CTE (id, myId, Name, NameCount)
AS (SELECT id,
myId,
Cast(Name AS VARCHAR(225)) Name,
1 NameCount
FROM (SELECT Row_number() OVER (PARTITION BY myId ORDER BY myId) AS id,
myId,
Name
FROM names) e
WHERE id = 1
UNION ALL
SELECT e1.id,
e1.myId,
Cast(Rtrim(CTE.Name) + ',' + e1.Name AS VARCHAR(225)) AS Name,
CTE.NameCount + 1 NameCount
FROM CTE
INNER JOIN (SELECT Row_number() OVER (PARTITION BY myId ORDER BY myId) AS id,
myId,
Name
FROM names) e1
ON e1.id = CTE.id + 1
AND e1.myId = CTE.myId)
SELECT myID,
Name
FROM (SELECT myID,
Name,
(Row_number() OVER (PARTITION BY myId ORDER BY namecount DESC)) AS id
FROM CTE) AS p
WHERE id = 1
Theo yêu cầu, đây là phương thức XML:
SELECT myId,
STUFF((SELECT ',' + rtrim(convert(char(50),Name))
FROM namestable b
WHERE a.myId = b.myId
FOR XML PATH('')),1,1,'') Names
FROM namestable a
GROUP BY myId