Bạn có thể sử dụng FOR XML PATH('')
như thế này:
DECLARE @TestData TABLE
(
address_desc NVARCHAR(100) NOT NULL
,people_id UNIQUEIDENTIFIER NOT NULL
);
INSERT @TestData
SELECT 'Murfreesboro, TN 37130', 'F15D1135-9947-4F66-B778-00E43EC44B9E'
UNION ALL
SELECT '11 Mohawk Rd., Burlington, MA 01803', 'C561918F-C2E9-4507-BD7C-00FB688D2D6E'
UNION ALL
SELECT 'Unknown, UN 00000', 'C561918F-C2E9-4507-BD7C-00FB688D2D6E'
UNION ALL
SELECT 'Memphis, TN 38133', '8ED8C601-5D35-4EB7-9217-012905D6E9F1'
UNION ALL
SELECT '44 Maverick St., Fitchburg, MA', '8ED8C601-5D35-4EB7-9217-012905D6E9F1';
SELECT a.people_id,
(SELECT SUBSTRING(
(SELECT ';'+b.address_desc
FROM @TestData b
WHERE a.people_id = b.people_id
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)')
,2
,4000)
) GROUP_CONCATENATE
FROM @TestData a
GROUP BY a.people_id
Kết quả:
people_id GROUP_CONCATENATE
------------------------------------ ------------------------------------------------------
F15D1135-9947-4F66-B778-00E43EC44B9E Murfreesboro, TN 37130
C561918F-C2E9-4507-BD7C-00FB688D2D6E 11 Mohawk Rd., Burlington, MA 01803;Unknown, UN 00000
8ED8C601-5D35-4EB7-9217-012905D6E9F1 Memphis, TN 38133;44 Maverick St., Fitchburg, MA