Có thể có các giải pháp đơn giản hơn để thực hiện việc này nhưng đây là một cách.
Cấu trúc bảng
create table Locations(LocationID int, Location varchar(50))
create table OtherTable(ID int, Locations varchar(max))
Dữ liệu thử nghiệm
insert into Locations values(1, 'Location <1>')
insert into Locations values(2, 'Location <2>')
insert into Locations values(3, 'Location <3>')
insert into Locations values(4, 'Location <4>')
insert into Locations values(5, 'Location <5>')
insert into OtherTable values (1, '')
insert into OtherTable values (2, '2')
insert into OtherTable values (3, '1, 3 ,5')
Truy vấn
;with cte as
(
select
T.ID,
coalesce(L.Location, '') as Location
from OtherTable as T
cross apply
(select cast('<r>'+replace(T.Locations, ',', '</r><r>')+'</r>' as xml)) LocXML(XMLCol)
cross apply
LocXML.XMLCol.nodes('r') LocID(IDCol)
left outer join Locations as L
on L.LocationID = LocID.IDCol.value('.', 'int')
)
select
C1.ID,
stuff((select ', '+C2.Location
from cte as C2
where C1.ID = C2.ID
for xml path(''), type).value('text()[1]', 'nvarchar(max)'), 1, 2, '') as Locations
from cte as C1
group by C1.ID
Kết quả
ID Locations
--- ----------------------------------------
1
2 Location <2>
3 Location <1>, Location <3>, Location <5>
