Truy vấn mysql:hiển thị tóm tắt tất cả các khoản thanh toán đã thực hiện và tổng số hóa đơn theo ngày

select
  x.date,
  sum(x.invoiceTotal) as invoiceTotal,
  sum(x.paymentsMade) as paymentMade
from
 (select
   i.date, 
   sum(i.rate * i.quantity /*?*/) as invoiceTotal,
   null as paymentMade    
 from
   invoice i
   inner join invoiceitem ii on ii.invoiceId = i.invoiceId
 group by
   i.date
 union all
 select
   p.date,
   null as invoiceTotal,
   sum(p.amount) as paymentMade    
 from
   payment p
 group by
   p.date) x
group by
  x.date
order by
  x.date