SQL:lặp qua cùng một bảng

một cái gì đó như thế này? FIDDLE để tham khảo

SELECT project_id,project_name,parent_id,recycle_bin,creater_id
FROM projectdetails AS pd1
JOIN(
    SELECT parent_id FROM projectdetails as pd
    WHERE pd.parent_id > 0 AND pd.recycle_bin > 1
) AS t ON t.parent_id = pd1.project_id

với dữ liệu mới .. NEW_FIDDLE

SELECT 
  if(pd1.recycle_bin >1, pd1.project_id, t.project_id) AS project_id,
  if(pd1.recycle_bin >1, pd1.project_name, t.project_name) AS project_name,
  if(pd1.recycle_bin >1, pd1.parent_id, t.parent_id) AS parent_id,
  if(pd1.recycle_bin >1, pd1.recycle_bin, t.recycle_bin) AS recycle_bin,
  if(pd1.recycle_bin >1, pd1.creater_id, t.creater_id) AS creater_id
FROM projectdetails AS pd1
JOIN(
  SELECT * FROM projectdetails AS pd
  WHERE pd.parent_id > 0 
    AND pd.recycle_bin > 1
) AS t ON t.parent_id = pd1.project_id
GROUP BY project_id

mà không sử dụng LAST_FIDDLE của IF

SELECT 
   pd1.project_id,
   pd1.project_name,
   pd1.parent_id,
   pd1.recycle_bin,
   pd1.creater_id
FROM projectdetails AS pd1
WHERE NOT EXISTS(
  SELECT pd.recycle_bin FROM projectdetails as pd
  WHERE pd1.parent_id = pd.project_id 
    AND pd.recycle_bin > 1
) AND pd1.creater_id = 7923 and pd1.recycle_bin > 1
GROUP BY pd1.project_id;